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return trueis correct around half of the time
assert IsEven(2) == True assert IsEven(4) == True assert IsEven(6) == TrueAll checks pass. LGTM
Just divide the number into its prime factors and then check if one of them is 2.
I remember coding actionscript in Flash and using modulo (%) to determine if a number was even or odd. It returns the remainder of the number divided by 2 and if it equals anything other than 0 then the number is odd.
Yeah. The joke is that this is the obvious solution always used in practise, but the programmer is that bad that they don’t know it and use some ridiculous alternative solutions instead.
I believe that’s the proper way to do it.
Zero people in this post get the YanDev reference
so nobody actually really got the joke. very sad Moment.
It’s really just us… I’ve seen the basic programming joke a bunch of times, but people really aren’t understanding the YanDev/font embellishment. Sad indeed.
I do :D
import re def is_even(i: int) -> bool: return re.match(r"-?\d*[02468]$", str(i)) is not NoneCursed
If number%2 == 0: return("Even") Else: return("odd")Deleted
Can’t you just
If (number % 2 == 0){return true}
but what if
numberisn’t an integer, or even a number at all? This code, and the improved code shared by the other user, could cause major problems under those conditions. Really, what you would want, is to validate thatnumberis actually an integer before performing the modulo, and if it isn’t, you want to throw an exception, because something has gone wrong.That’s exactly what that NPM module does. And this is why it’s not a bad thing to use packages/modules for even very simple tasks, because they help to prevent us from making silly mistakes.
ah the joys of loosely typed languages
